Thesauros Literature mathematics Στοιχεῖα

Στοιχεῖα

Στοιχεῖα Euclid

Book 9

13 For, if E is measured by another, and E measures D, that other will also measure D; so that it will also measure A [IX. 12], which is prime, though it is not the same with it: which is impossible.
13 Therefore A measures E.
13 And, since E measures D, let it measure it according to F.
13 I say that F is not the same with any of the numbers A, B, C.
13 For, if F is the same with one of the numbers A, B, C, and measures D according to E, therefore one of the numbers A, B, C also measures D according to E.
13 But one of the numbers A, B, C measures D according to some one of the numbers A, B, C; [IX. 11] therefore E is also the same with one of the numbers A, B, C: which is contrary to the hypothesis.
13 Therefore F is not the same as any one of the numbers A, B, C.
13 Similarly we can prove that F is measured by A, by proving again that F is not prime.
13 For, if it is, and measures D, it will also measure A [IX. 12], which is prime, though it is not the same with it: which is impossible; therefore F is not prime.
13 Therefore it is composite.
13 But any composite number is measured by some prime number; [VII. 31] therefore F is measured by some prime number.
13 I say next that it will not be measured by any other prime except A.
13 For, if any other prime number measures F, and F measures D, that other will also measure D; so that it will also measure A [IX. 12], which is prime, though it is not the same with it: which is impossible.
13 Therefore A measures F.
13 And, since E measures D according to F, therefore E by multiplying F has made D.
13 But, further, A has also by multiplying C made D; [IX. 11] therefore the product of A, C is equal to the product of E, F.
13 Therefore, proportionally, as A is to E, so is F to C. [VII. 19]
13 But A measures E; therefore F also measures C.
13 Let it measure it according to G.
13 Similarly, then, we can prove that G is not the same with any of the numbers A, B, and that it is measured by A.
13 And, since F measures C according to G therefore F by multiplying G has made C.

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