Book 9
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For let the cube number A by multiplying any number B make the cube number C; I say that B is cube.
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For let A by multiplying itself make D; therefore D is cube. [IX. 3]
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Now, since A by multiplying itself has made D, and by multiplying B has made C, therefore, as A is to B, so is D to C. [VII. 17]
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And since D, C are cube, they are similar solid numbers.
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Therefore two mean proportional numbers fall between D, C. [VIII. 19]
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And, as D is to C, so is A to B; therefore two mean proportional numbers fall between A, B also. [VIII. 8]
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And A is cube; therefore B is also cube. [VIII. 23]
PROPOSITION 6.
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If a number by multiplying itself make a cube number, it will itself also be cube.
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For let the number A by multiplying itself make the cube number B; I say that A is also cube.
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For let A by multiplying B make C.
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Since, then, A by multiplying itself has made B, and by multiplying B has made C, therefore C is cube.
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And, since A by multiplying itself has made B, therefore A measures B according to the units in itself.
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But the unit also measures A according to the units in it.
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Therefore, as the unit is to A, so is A to B. [VII. Def. 20]
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And, since A by multiplying B has made C, therefore B measures C according to the units in A.
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But the unit also measures A according to the units in it.
6
Therefore, as the unit is to A, so is B to C. [VII. Def. 20]
6
But, as the unit is to A, so is A to B; therefore also, as A is to B, so is B to C.
6
And, since B, C are cube, they are similar solid numbers.
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Therefore there are two mean proportional numbers between B, C. [VIII. 19]
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And, as B is to C, so is A to B.
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Therefore there are two mean proportional numbers between A, B also. [VIII. 8]
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And B is cube; therefore A is also cube. [cf. VIII. 23] Q. E. D.
PROPOSITION 7.
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If a composite number by multiplying any number make some number, the product will be solid.
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For let the composite number A by multiplying any number B make C; I say that C is solid.
7
For, since A is composite, it will be measured by some number. [VII. Def. 13]